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3x^2+33x-78=0
a = 3; b = 33; c = -78;
Δ = b2-4ac
Δ = 332-4·3·(-78)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-45}{2*3}=\frac{-78}{6} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+45}{2*3}=\frac{12}{6} =2 $
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